1 | initial version |
If G
is your graph, then G.to_dictionary()
does what you're asking for, I believe.
2 | No.2 Revision |
If G
is your graph, then G.to_dictionary()
does what you're asking for, I believe.
sage: d = {0: [1, 5, 7, 8, 11],
....: 1: [0, 2, 5, 6, 8],
....: 2: [1, 3, 6, 8, 9],
....: 3: [2, 4, 6, 9, 10],
....: 4: [3, 5, 6, 10, 11],
....: 5: [0, 1, 4, 6, 11],
....: 6: [1, 2, 3, 4, 5],
....: 7: [0, 8, 9, 10, 11],
....: 8: [0, 1, 2, 7, 9],
....: 9: [2, 3, 7, 8, 10],
....: 10: [3, 4, 7, 9, 11],
....: 11: [0, 4, 5, 7, 10]}
sage: G = Graph(d)
sage: G.to_dictionary()
{0: [1, 5, 7, 8, 11],
1: [0, 2, 5, 6, 8],
2: [1, 3, 6, 8, 9],
3: [2, 4, 6, 9, 10],
4: [3, 5, 6, 10, 11],
5: [0, 1, 4, 6, 11],
6: [1, 2, 3, 4, 5],
7: [0, 8, 9, 10, 11],
8: [0, 1, 2, 7, 9],
9: [2, 3, 7, 8, 10],
10: [3, 4, 7, 9, 11],
11: [0, 4, 5, 7, 10]}
sage: G.to_dictionary() == d
True