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 | 1 | initial version |
Since $y$ is a function of $x$, so is $y'$, and $f$ is a function of $x$ and $x$ alone : fixing $x$ fixes $y(x)$ and $y'(x)$.
End of story.
HTH,
| | 1 | initial version |
Since $y$ is a function of $x$, so is $y'$, and $f$ is a function of $x$ and $x$ alone : fixing $x$ fixes $y(x)$ and $y'(x)$.
End of story.
HTH,
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