Revision history [back]
 | 1 | initial version |
This question has nothing to do with Sage, and furthermore what is asked is impossible. We have $\log_N(2^{58}) \leq \alpha <\log_N(2^{59})$ and $\delta < 2-\sqrt{\log_N(2^{58})}$. Hence, $$\alpha+\delta < 2 + \log_N(2^{59}) - \sqrt{\log_N(2^{58})}\approx 1.797.$$ On the other hand, since $ed > \phi$, we have $$\alpha+\delta > \log_N(\phi)\approx 2.000.$$
