1 | initial version |
Instead of plot(h(x), x, -5, 5)
, try plot(h, (-5, 5))
.
Note: the function may not be what you want for negative x
.
Here is another option defining h
as a symbolic function without a while loop.
In this case, both plot(h, (-5, 5))
and plot(h(x), (-5, 5))
give a correct plot.
sage: h(x) = x - 2 * floor((x + 1) / 2)
sage: plot(h, (-5, 5), aspect_ratio=1)
2 | No.2 Revision |
Instead of plot(h(x), x, -5, 5)
, try plot(h, (-5, 5))
.
Note: the function may not be what you want for negative x
.
Here is another option defining h
as a symbolic function without a while loop.
In this case, both plot(h, (-5, 5))
and plot(h(x), (-5, 5))
give a correct plot.
sage: h(x) = x abs(x - 2 * floor((x + 1) / 2)
2))
sage: plot(h, (-5, 5), aspect_ratio=1)
3 | No.3 Revision |
Instead of plot(h(x), x, -5, 5)
, try plot(h, (-5, 5))
.
Note: the function may not be what you want for negative x
.
Here is another option defining One could also define h
as a symbolic function without a while loop.
Here are two examples of doing that.
Using the floor function:
sage: h(x) = abs(x - 2 * floor((x + 1) / 2))
sage: plot(h, (-5, 5), aspect_ratio=1)
sage: plot(h(x), (-5, 5), aspect_ratio=1)
Using trigonometric functions:
sage: h(x) = arccos(cos(x*pi))/pi
sage: plot(h, (-5, 5), aspect_ratio=1)
sage: plot(h(x), (-5, 5), aspect_ratio=1)
In this case, both plot(h, (-5, 5))
and plot(h(x), (-5, 5))
give a correct plot.
sage: h(x) = abs(x - 2 * floor((x + 1) / 2))
sage: plot(h, (-5, 5), aspect_ratio=1)