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answered 2 years ago

Max Alekseyev gravatar image

The given equation can be rewritten as 3(2y+1)(2z+1)=(2x+1)(2w+1), which suggests that solutions can be generated by first fixing values of y,z and thus n:=3(2y+1)(2z+1), then running d over the divisors of n, and setting x=d12 and w=n/d12 .