1 | initial version |
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
2 | No.2 Revision |
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
So if you have $(A, b)$ such that $Ax \leq b$ is your polyhedron, then use $(-A, b)$ as input to Sage's Polyhedron
.
3 | No.3 Revision |
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
So if you have $(A, b)$ such that $Ax \leq b$ is your polyhedron, then use $(-A, $(A', b)$ as input to Sage's where $A'=-A$ are such that $A'x + b \geq 0$ is also your polyhedron.Polyhedron
.
4 | No.4 Revision |
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
So if you have $(A, b)$ such that $Ax \leq b$ is your polyhedron, then $(A', b)$ where $A'=-A$ are is such that $A'x + b \geq 0$ is also your polyhedron.
5 | No.5 Revision |
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
So if you have $(A, b)$ such that $Ax \leq b$ is your polyhedron, then the pair $(A', b)$ b)$, where $A'=-A$ $A'=-A$, is such that $A'x + b \geq 0$ is also your polyhedron.