Revision history [back]
 | 1 | initial version |
cos(th)*sin(th)==f is equivalent to th==arcsin(2*f), and so substitution eq.subs({th:arcsin(2*f)}) should do the job.
| | 2 | No.2 Revision |
cos(th)*sin(th)==f is equivalent to th==arcsin(2*f)th==arcsin(2*f)/2eq.subs({th:arcsin(2*f)})eq.subs({th:arcsin(2*f)/2})
