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The following yields the same result as your function perRandC:
G = SymmetricGroup(5) # create the symmetric group on 5
perm = G((1,2)) # create the permutation (1, 2) in G, i.e. perm just swaps 1 and 2
M.permute_rows_and_columns(perm, perm)
show(M)
G contains all possible permutations of {1,2,3,4,5}. Note that permute_rows_and_columns works with 1-based indices, i.e. since we want to swap the 0th and 1st row we have to use (1,2). Alternatively, using the same method as in the documentation, we could also do:
G = PermutationGroup(['(1,2)'])
perm = G.gens()[0]
M.permute_rows_and_columns(perm, perm)
show(M)
All three yield the same result.
