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answered 4 years ago
R(f)=x^m+q is trying to build a symbolic function named R with argument f. Just f = x^m+q would work
updated 4 years ago
R(f)=x^m+q R(f)=x^m+q is trying to build a symbolic function named R with argument f. Just f = x^m+q x^m+q would work
R(f)=x^m+q
f = x^m+q x^m+q