1 | initial version |
The indentation in your second code block is wrong, but if you fix that (don't indent while
, indent all of the lines after it), it works, at least for me. The code can also be rewritten a few ways:
no need for the variable i
:
for a in List1: Result = List2[0].coefficient(a) List3.append(Result)
in fact, no need for an explicit loop at all, using list comprehension instead:
List3 = [List2[0].coefficient(a) for a in List1]
By the way, there are other ways to get at the coefficients. For example:
a = x^2 + 2*y^2 + 3*z^2
for b in a:
print(b)
will print
(1, x^2)
(2, y^2)
(3, z^2)
You can get the same information using list comprehension, [b for b in a]
or in fact just list(a)
.
2 | No.2 Revision |
The indentation in your second code block is wrong, but if you fix that (don't indent while
, indent all of the lines after it), it works, at least for me. The code can also be rewritten a few ways:
no
No
need for the variablei
:
for a in List1:
Result = List2[0].coefficient(a)
in
In
fact, no need for an explicit loop at all, using list comprehension instead:
List3 = [List2[0].coefficient(a) for a in By the way, there are other ways to get at the coefficients. For example:
a = x^2 + 2*y^2 + 3*z^2
for b in a:
print(b)
will print
(1, x^2)
(2, y^2)
(3, z^2)
You can get the same information using list comprehension, [b for b in a]
or in fact just list(a)
.
3 | No.3 Revision |
The indentation in your second code block is wrong, but if you fix that (don't indent while
, indent all of the lines after it), it works, at least for me. The code can also be rewritten a few ways:
No need for the variable i
:
for a in List1:
Result = List2[0].coefficient(a)
List3.append(Result)
In fact, no need for an explicit loop at all, using list comprehension instead:
List3 = [List2[0].coefficient(a) for a in List1]
By the way, there are other ways to get at the coefficients. For example:
a = x^2 + 2*y^2 + 3*z^2
for b in a:
print(b)
will print
(1, x^2)
(2, y^2)
(3, z^2)
You can get the same information using list comprehension, [b for b in a]
, or in fact just list(a)
.