Revision history [back]
 | 1 | initial version |
I did:
a = 1 + ( 1/2 + i*sqrt(3)/2 )^3
Then
bool(a == 0)
returns True, and
a.simpify_full()
returns 0. Try typing a.simplify<TAB> to see the list of possible simplifications.
| | 1 | initial version |
I did:
a = 1 + ( 1/2 + i*sqrt(3)/2 )^3
Then
bool(a == 0)
returns True, and
a.simpify_full()
returns 0. Try typing a.simplify<TAB> to see the list of possible simplifications.
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