Revision history [back]
 | 1 | initial version |  |
I did:
a = 1 + ( 1/2 + i*sqrt(3)/2 )^3Then
bool(a == 0)returns True, and
a.simpify_full()returns 0. Try typing a.simplify<TAB> to see the list of possible simplifications.
| | 1 | initial version | |
I did:
a = 1 + ( 1/2 + i*sqrt(3)/2 )^3Then
bool(a == 0)returns True, and
a.simpify_full()returns 0. Try typing a.simplify<TAB> to see the list of possible simplifications.
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.