Revision history [back]
 | 1 | initial version |
The quick and dirty code for this is:
x,a,c = var('x a c') assume(x>0,a>0,c>0) solve(x^a - c== 0,x)
| | 2 | No.2 Revision |
The quick and dirty code for this is:
x,a,c = var('x a c') assume(x>0,a>0,c>0) solve(x^a - c== 0,x)
| | 3 | No.3 Revision |
The quick and dirty code for this is:
| | 4 | No.4 Revision |
The quick and dirty code for this is:
x,a,c = var('x a c')
assume(x>0,a>0,c>0)
solve(x^a - c== 0,x)
