Loading [MathJax]/jax/output/HTML-CSS/jax.js
Ask Your Question

Revision history [back]

click to hide/show revision 1
initial version

answered 5 years ago

castor gravatar image

The elliptic curve E1:y2=x3x/25+9/125 is isomorphic to the one E2:Y2=X325X+953, here we have X=25x. Integral points on E1 are integral points on E2. The latter can be computed via Sage.

E=EllipticCurve([-25,9*5^3])
E.integral_points()
[(4 : 33 : 1)]

Hence the only candidates points are (4/25:±33/125:1) on your curve. Therefore there are no integral points.

click to hide/show revision 2
No.2 Revision

The elliptic curve E1:y2=x3x/25+9/125 is isomorphic to the one E2:Y2=X325X+953, here we have X=25x. Integral points on E1 are integral points on E2. The latter can be computed via Sage.

E=EllipticCurve([-25,9*5^3])
E.integral_points()
[(4 : 33 : 1)]

Hence the only candidates points are (4/25:±33/125:1) on your curve. Therefore there are no integral points.