|   | 1 |  initial version  | 
Hello, @Cyrille! Try the following:
gr = Polyhedron(ieqs=[(10,-1,0), (-12,0,1)])
p1 = gr.plot()
x_0, x_1 = var('x_0 x_1')
lin = solve([70==6*x_0+18*x_1], x_1, solution_dict=True)
p2 = plot(lin[0][x_1], (x_0,8,14))
p1 + p2
Notice I have added solution_dict=True, which makes lin a list of dictionaries of solutions:
[{x_1: -1/3*x_0 + 35/9}]
In order to plot it, first extract the dictionary from the list (that is done with lin[0]); we get
{x_1: -1/3*x_0 + 35/9}
Finally, we extract the equation you want to plot (that is done with lin[0][x_1]); we get
-1/3*x_0 + 35/9
That is what I used in the plot command.
Note: It is not necessary to use (x_0, 8, 14) in the plot command; you can use (x, 8, 14). I did that to be consistent with notation.
There are a couple of things that bother me:
x_1 has more than one solution.Problem 2 is solved using tmontiel's suggestion.
There may be an alternative way to achieve the same thing. May I ask: what are you trying to achieve?
 Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
 
                
                Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.