Revision history [back]
 | 1 | initial version |
["rr_%d%d"%(i,i-1) for i in [1..n]]
is the right solution
| | 2 | No.2 Revision |
this:
["rr_%d%d"%(i,i-1) for i in [1..n]][1..n]]
is the right solution
| | 1 | initial version |
["rr_%d%d"%(i,i-1) for i in [1..n]]
is the right solution
| | 2 | No.2 Revision |
this:
["rr_%d%d"%(i,i-1) for i in [1..n]][1..n]]
is the right solution
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