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 | 1 | initial version |
Yes, you can do this:
sage: B = C.right_kernel().matrix()
sage: D = block_matrix([[C],[B]], subdivide=True)
| | 1 | initial version |
Yes, you can do this:
sage: B = C.right_kernel().matrix()
sage: D = block_matrix([[C],[B]], subdivide=True)
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