1 | initial version |
This is tricky, but it can be done. The idea is to replace (in the expression tree) derivatives of $f$ with respect to $t$ by the right-hand side of the equation, substituted into itself as many times as there are derivatives with respect to $t$ minus one, and finally replacing $f$ by the derivative of $f$ with respect to the remaining variables (if any).
My attempt to implement this (based on SubstituteFunction
) is below, with an example (your example) in the docstring.
from sage.symbolic.expression_conversions import ExpressionTreeWalker
from sage.symbolic.operators import FDerivativeOperator
class SubstituteEvolutionaryPDE(ExpressionTreeWalker):
def __init__(self, ex, pde):
"""
A class that walks the tree and replaces derivatives of `f` with
respect to `t` by the right-hand side of an evolutionary PDE.
EXAMPLES::
sage: var('x,t'); f = function('f'); g = function('g')
sage: pde = diff(f(t,x),t) == 1/2*diff(f(t,x),x,x)
sage: s = SubstituteEvolutionaryPDE(0, pde)
sage: h = g(diff(f(t,x),t), diff(f(t,x),t,x))
sage: s(h)
g(1/2*diff(f(t, x), x, x), 1/2*diff(f(t, x), x, x, x))
ASSUMPTION::
``pde`` is of the form ``diff(f(t,...),t) == ...`` and the first
argument of ``f`` is always ``t``.
"""
self.f = integrate(pde.lhs(), t).operator()
self.rhs = pde.rhs()
self.ex = ex
def derivative(self, ex, operator):
if operator.function() == self.f and 0 in operator.parameter_set(): # f is differentiated with respect to t
t_derivatives = [p for p in operator.parameter_set() if p == 0] # (assumes t is the first argument)
result = self.rhs
for _ in range(len(t_derivatives)-1):
result = result.substitute_function(self.f, self.rhs)
if len(t_derivatives) < len(operator.parameter_set()): # derivatives w.r.t variables other than t
other_derivatives = [p for p in operator.parameter_set() if not p == 0] # (assumes t is the first argument)
new_operator = FDerivativeOperator(operator.function(), other_derivatives)
result = result.substitute_function(self.f, new_operator(*[self(_) for _ in ex.operands()]))
return result
else:
return operator(*[self(_) for _ in ex.operands()])
2 | No.2 Revision |
This is tricky, but it can be done. The idea is to replace (in the expression tree) derivatives of $f$ with respect to $t$ by the right-hand side of the equation, substituted into itself as many times as there are derivatives with respect to $t$ minus one, and finally replacing $f$ by the derivative of $f$ with respect to the remaining variables (if any).
My attempt to implement this (based on SubstituteFunction
) is below, with an example (your example) in the docstring.
docstring.
from sage.symbolic.expression_conversions import ExpressionTreeWalker
from sage.symbolic.operators import FDerivativeOperator
FDerivativeOperator
class SubstituteEvolutionaryPDE(ExpressionTreeWalker):
def __init__(self, ex, pde):
pde, t):
"""
A class that walks the tree and replaces derivatives of `f` with
respect to `t` by the right-hand side of an evolutionary PDE.
EXAMPLES::
sage: var('x,t'); f = function('f'); g = function('g')
sage: pde = diff(f(t,x),t) == 1/2*diff(f(t,x),x,x)
sage: s = SubstituteEvolutionaryPDE(0, pde)
pde, t)
sage: h = g(diff(f(t,x),t), diff(f(t,x),t,x))
sage: s(h)
g(1/2*diff(f(t, x), x, x), 1/2*diff(f(t, x), x, x, x))
ASSUMPTION::
``pde`` is of the form ``diff(f(t,...),t) == ...`` and the first
argument of ``f`` is always ``t``.
"""
self.f = integrate(pde.lhs(), t).operator()
self.rhs = pde.rhs()
self.ex = ex
def derivative(self, ex, operator):
if operator.function() == self.f and 0 in operator.parameter_set(): # f is differentiated with respect to t
t_derivatives = [p for p in operator.parameter_set() if p == 0] # (assumes t is the first argument)
result = self.rhs
for _ in range(len(t_derivatives)-1):
result = result.substitute_function(self.f, self.rhs)
if len(t_derivatives) < len(operator.parameter_set()): # derivatives w.r.t variables other than t
other_derivatives = [p for p in operator.parameter_set() if not p == 0] # (assumes t is the first argument)
new_operator = FDerivativeOperator(operator.function(), other_derivatives)
result = result.substitute_function(self.f, new_operator(*[self(_) for _ in ex.operands()]))
return result
else:
return operator(*[self(_) for _ in ex.operands()])
3 | No.3 Revision |
This is tricky, but it can be done. The idea is to replace (in the expression tree) derivatives of $f$ with respect to $t$ by the right-hand side of the equation, substituted into itself as many times as there are derivatives with respect to $t$ minus one, and finally replacing $f$ by the derivative of $f$ with respect to the remaining variables (if any).
My attempt to implement this (based on SubstituteFunction
) is below, with an example (your example) in the docstring.
docstring.
from sage.symbolic.expression_conversions import ExpressionTreeWalker
from sage.symbolic.operators import FDerivativeOperator
FDerivativeOperator
class SubstituteEvolutionaryPDE(ExpressionTreeWalker):
def __init__(self, ex, pde, t):
"""
A class that walks the tree and replaces derivatives of `f` with
respect to `t` by the right-hand side of an evolutionary PDE.
EXAMPLES::
sage: var('x,t'); f = function('f'); g = function('g')
sage: pde = diff(f(t,x),t) == 1/2*diff(f(t,x),x,x)
sage: s = SubstituteEvolutionaryPDE(0, pde, t)
sage: h = g(diff(f(t,x),t), diff(f(t,x),t,x))
sage: s(h)
g(1/2*diff(f(t, x), x, x), 1/2*diff(f(t, x), x, x, x))
ASSUMPTION::
``pde`` is of the form ``diff(f(t,...),t) == ...`` and the first
argument of ``f`` is always ``t``.
"""
self.f = integrate(pde.lhs(), t).operator()
self.rhs = pde.rhs()
self.ex = ex
def derivative(self, ex, operator):
if operator.function() == self.f and 0 in operator.parameter_set(): # f is differentiated with respect to t
t_derivatives = [p for p in operator.parameter_set() if p == 0] # (assumes t is the first argument)
result = self.rhs
for _ in range(len(t_derivatives)-1):
result = result.substitute_function(self.f, self.rhs)
if len(t_derivatives) < len(operator.parameter_set()): # derivatives w.r.t variables other than t
other_derivatives = [p for p in operator.parameter_set() if not p == 0] # (assumes t is the first argument)
new_operator = FDerivativeOperator(operator.function(), other_derivatives)
result = result.substitute_function(self.f, new_operator(*[self(_) for _ in ex.operands()]))
return result
else:
return operator(*[self(_) for _ in ex.operands()])
4 | No.4 Revision |
This is tricky, but it can be done. The idea is to replace (in the expression tree) derivatives of $f$ (with at least one derivative with respect to $t$ $t$) by the right-hand side of the equation, substituted into itself as many times as there are derivatives with respect to $t$ minus one, and finally replacing $f$ by the derivative of $f$ with respect to the remaining variables (if any).
My attempt to implement this (based on SubstituteFunction
) is below, with an example (your example) in the docstring.
from sage.symbolic.expression_conversions import ExpressionTreeWalker
from sage.symbolic.operators import FDerivativeOperator
class SubstituteEvolutionaryPDE(ExpressionTreeWalker):
def __init__(self, ex, pde, t):
"""
A class that walks the tree and replaces derivatives of `f` with
respect to `t` by the right-hand side of an evolutionary PDE.
EXAMPLES::
sage: var('x,t'); f = function('f'); g = function('g')
sage: pde = diff(f(t,x),t) == 1/2*diff(f(t,x),x,x)
sage: s = SubstituteEvolutionaryPDE(0, pde, t)
sage: h = g(diff(f(t,x),t), diff(f(t,x),t,x))
sage: s(h)
g(1/2*diff(f(t, x), x, x), 1/2*diff(f(t, x), x, x, x))
ASSUMPTION::
``pde`` is of the form ``diff(f(t,...),t) == ...`` and the first
argument of ``f`` is always ``t``.
"""
self.f = integrate(pde.lhs(), t).operator()
self.rhs = pde.rhs()
self.ex = ex
def derivative(self, ex, operator):
if operator.function() == self.f and 0 in operator.parameter_set(): # f is differentiated with respect to t
t_derivatives = [p for p in operator.parameter_set() if p == 0] # (assumes t is the first argument)
result = self.rhs
for _ in range(len(t_derivatives)-1):
result = result.substitute_function(self.f, self.rhs)
if len(t_derivatives) < len(operator.parameter_set()): # derivatives w.r.t variables other than t
other_derivatives = [p for p in operator.parameter_set() if not p == 0] # (assumes t is the first argument)
new_operator = FDerivativeOperator(operator.function(), other_derivatives)
result = result.substitute_function(self.f, new_operator(*[self(_) for _ in ex.operands()]))
return result
else:
return operator(*[self(_) for _ in ex.operands()])
5 | No.5 Revision |
This is tricky, but it can be done. The idea is to replace (in the expression tree) derivatives of $f$ (with at least one derivative with respect to $t$) by the right-hand side of the equation, substituted into itself as many times as there are derivatives with respect to $t$ minus one, and finally replacing $f$ by the derivative of $f$ with respect to the remaining variables (if any).
My attempt to implement this (based on SubstituteFunction
) is below, with an example (your example) in the docstring.
from sage.symbolic.expression_conversions import ExpressionTreeWalker
from sage.symbolic.operators import FDerivativeOperator
class SubstituteEvolutionaryPDE(ExpressionTreeWalker):
def __init__(self, ex, pde, t):
"""
A class that walks the tree and replaces derivatives of `f` with
respect to `t` by the right-hand side of an evolutionary PDE.
EXAMPLES::
sage: var('x,t'); f = function('f'); g = function('g')
sage: pde = diff(f(t,x),t) == 1/2*diff(f(t,x),x,x)
sage: s = SubstituteEvolutionaryPDE(0, pde, SubstituteEvolutionaryPDE(pde, t)
sage: h = g(diff(f(t,x),t), diff(f(t,x),t,x))
sage: s(h)
g(1/2*diff(f(t, x), x, x), 1/2*diff(f(t, x), x, x, x))
ASSUMPTION::
``pde`` is of the form ``diff(f(t,...),t) == ...`` and the first
argument of ``f`` is always ``t``.
"""
f_expr = integrate(pde.lhs(), t)
self.f = integrate(pde.lhs(), t).operator()
f_expr.operator()
self.args = f_expr.operands()
self.rhs = pde.rhs()
self.ex = ex
def derivative(self, ex, operator):
if operator.function() == self.f and 0 in operator.parameter_set(): # f is differentiated with respect to t
t_derivatives = [p for p in operator.parameter_set() if p == 0] # (assumes t is the first argument)
result = self.rhs
for _ in range(len(t_derivatives)-1):
result = result.substitute_function(self.f, self.rhs)
self.rhs.function(*self.args))
if len(t_derivatives) < len(operator.parameter_set()): # derivatives w.r.t variables other than t
other_derivatives = [p for p in operator.parameter_set() if not p == 0] # (assumes t is the first argument)
new_operator = FDerivativeOperator(operator.function(), other_derivatives)
result = result.substitute_function(self.f, new_operator(*[self(_) for _ in ex.operands()]))
ex.operands()]).function(*self.args))
return result
else:
return operator(*[self(_) for _ in ex.operands()])
Edit: updated to use substitute_function
correctly (the second argument should also be a function).