1 | initial version |
Note that this is not the problem with assume
but with symbolic expression involving more than one comparison operator:
sage: 0 <= x <= 1/2
0 <= x
sage: e = 0 <= x <= 1/2
sage: e.operator()
<built-in function le>
sage: e.operands()
[0, x]
Note the following weird behaviour:
sage: assume(0 <= x)
sage: 0 <= x <= 1/2
x <= (1/2)
2 | No.2 Revision |
This is clearly a bug, thanks for reporting ! See trac ticket 24726
Note that this is actually not the problem with assume
but with symbolic expression involving more than one comparison operator:
sage: 0 <= x <= 1/2
0 <= x
sage: e = 0 <= x <= 1/2
sage: e.operator()
<built-in function le>
sage: e.operands()
[0, x]
Note the following weird behaviour:
sage: assume(0 <= x)
sage: 0 <= x <= 1/2
x <= (1/2)
3 | No.3 Revision |
This is clearly a bug, thanks for reporting ! See trac ticket 24726
Note that this is actually not the problem with assume
but with symbolic expression involving more than one comparison operator:
sage: 0 <= x <= 1/2
0 <= x
sage: e = 0 <= x <= 1/2
sage: e.operator()
<built-in function le>
sage: e.operands()
[0, x]
Note the following weird behaviour:
sage: assume(0 <= x)
sage: 0 <= x <= 1/2
x <= (1/2)
This is because now 0 <= x
is evaluated to True
, and True and something
returns something
.