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answered 7 years ago

dan_fulea gravatar image

We write x=75000+X ,y=200000+Y , and the new function to maximize on X,Y0 is the following function Q(X,Y):

sage: var( 'x,y,X,Y' );
sage: P(x,y) = 5/100*x*(1-x/150000-8/10^7*x*y) + 8/100*y*(1-y/200000-8/10^7*x*y)
sage: Q(X,Y) = P(X+75000, Y+200000).expand()
sage: Q(X,Y)
-1/25000000*X^2*Y - 1/15625000*X*Y^2 - 24001/3000000*X^2 - 79/2500*X*Y - 12001/2500000*Y^2 - 3760*X - 53627/25*Y - 236998125

The maximal value for Q is taken at the "corner" (X,Y)=(0,0), because all monomials appearing in total degree 1 have negative coefficients, so the maximal value for both P and Q is - 236998125, taken at "the one or the other corner".

Note: The theory tells us to search for the absolute extremal values

  • in the inner of the closed definition domain, by searching all local extremal values, obtained as a solution of Px=Py=0, and

  • at the (finite and/or infinite) boundary of it, by setting x=75000, x=, y=200000, y=, and computing here, in each of the four cases the supremum.

In our case there are no inner extremal points:

sage: for sol in solve( [diff(P,x) == 0, diff(P,y) == 0], [x,y] ):
....:     print sol
....:     
[x == 816.8214285714286, y == 506.0324074074074]
[x == -816.2645502645503, y == -514.5402298850574]
[x == (13.33265402759081 + 1414.015105182754*I), y == (3.906674551362281 - 883.7900965450355*I)]
[x == (13.33265402759081 - 1414.015105182754*I), y == (3.906674551362281 + 883.7900965450355*I)]

and no solution is in the inner domain.

Also there are no maximal values at the infinite boundaries, since P for either x or y going to +.

For the remained boundaries, we can set x=75000, respectivel y=200000, getting two new maximization problems in the simpler lower dimension...