1 | initial version |
When you write R = SR.var('R')
, the left-hand V
is a Python name pointing to the right-hand SR.var('V')
, which is a symbolic expression. Then when you write R = 3
, the Python name R
points to the integer 3
, so there is no relationship anymore between R
and SR.var('R')
:
sage: R = SR.var('R')
sage: type(R)
<type 'sage.symbolic.expression.Expression'>
sage: R = 3
sage: type(R)
<type 'sage.rings.integer.Integer'>
If you want to substitute R
with 3
in I
, you should do:
sage: I.substitute({R:3})
1/3*V
2 | No.2 Revision |
When you write R = SR.var('R')
, the left-hand
is a Python name pointing to the right-hand VR
, which is a symbolic expression. Then when you write SR.var('V')SR.var('R')R = 3
, the Python name R
points to the integer 3
, so there is no relationship anymore between R
and SR.var('R')
:
sage: R = SR.var('R')
sage: type(R)
<type 'sage.symbolic.expression.Expression'>
sage: R = 3
sage: type(R)
<type 'sage.rings.integer.Integer'>
If you want to substitute R
with 3
in I
, you should do:
sage: I.substitute({R:3})
1/3*V