1 | initial version |
The problem is that the value of arr[0]
is y0(x)
, which is an expression consisting of a function evaluated at x
. That's not the kind of functions that substitute_function
deals with. You can use subs
for that:
sage: square(arr[0]).subs(arr[0]==temp(x))
sin(x)^2
You are not the first person who get tripped up by the confusing fact that function('f',x)
doesn't return a function but a function evaluated at (something). To get something that actually is a function, use function('f')
. You can still evaluate that at x
by writing function('f')(x)
. See http://trac.sagemath.org/ticket/17447 .