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 | 1 | initial version |
If f is a symbolic function, you can get its Taylor expansion as follows:
sage: f = log((1-x)/(1-2*x))
sage: f.taylor(x,0,5)
31/5*x^5 + 15/4*x^4 + 7/3*x^3 + 3/2*x^2 + x
Then you can get its k^th coefficient as follows:
sage: f.taylor(x,0,5).coefficient(x^3)
7/3
| | 2 | No.2 Revision |
If f is a symbolic function, you can get its Taylor expansion as follows:
sage: f = log((1-x)/(1-2*x))
sage: f.taylor(x,0,5)
31/5*x^5 + 15/4*x^4 + 7/3*x^3 + 3/2*x^2 + x
Then you can get its k^th coefficient as follows:
sage: f.taylor(x,0,5).coefficient(x^3)
7/3
Or:
sage: f.taylor(x,0,5).coefficients()
[[1, 1], [3/2, 2], [7/3, 3], [15/4, 4], [31/5, 5]]
sage: f.taylor(x,0,5).list()
[0, 1, 3/2, 7/3, 15/4, 31/5]
