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You can kill the computation, for Sage is apparently trying to build all of these sets in order to count them. This is the default behaviour (and not always a very good idea) when no .cardinality() method has been implemented specifically for this problem.

Here, the number of submultiset of [0..52] containing at most twice the same element is at least the number of subsets of 53, i.e. at least 2^53. That is already too much.

If you know how this value should be computed, however, you are welcome to add this missing feature into Sage !

http://www.sagemath.org/doc/developer/