Revision history [back]
 | 1 | initial version |
The author of this question intends for you to plug 5 in for x and k in for y. If you do this, you will obtain
2(5) + k - 7 = 0 10 + k - 7 = 0 3 + k = 0 k = -3
We can check our work by confirming that (5, -3) is a solution to 2x + y - 7 = 0. 2(5) + (-3) - 7 = 10 - 3 - 7 = 7 - 7 = 0.
| | 2 | No.2 Revision |
The author of this question intends for you to plug 5 in for x and k in for y. If you do this, you will obtain
2(5) + k - 7 = 0
0
10 + k - 7 = 0
0
3 + k = 0
0
k = -3
We can check our work by confirming that (5, -3) is a solution to 2x + y - 7 = 0.
2(5) + (-3) - 7 = 10 - 3 - 7 = 7 - 7 = 0.