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 | 1 | initial version |
Since you named one variable n I assume you meant integer. But even this has infinitely many solutions! Sage can give you them for specific n:
sage: [solve(x^n==2*x,x) for n in range(1,5)]
[[x == 0],
[x == 0, x == 2],
[x == -sqrt(2), x == sqrt(2), x == 0],
[x == 1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == -1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == 2^(1/3), x == 0]]
| | 2 | No.2 Revision |
Since you named one variable n I assume you meant integer. But even this has infinitely many solutions! Sage can give you them for specific n:
sage: [solve(x^n==2*x,x) for n in range(1,5)]
[[x == 0],
[x == 0, x == 2],
[x == -sqrt(2), x == sqrt(2), x == 0],
[x == 1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == -1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == 2^(1/3), x == 0]]
