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 | 1 | initial version |  |
How about assigning the vertex itself as the position?
G=graphs.GridGraph([8,12])
G.show(pos=dict([(v,v) for v in G.vertices()]))| | 1 | initial version | |
How about assigning the vertex itself as the position?
G=graphs.GridGraph([8,12])
G.show(pos=dict([(v,v) for v in G.vertices()]))
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