![]() | 1 | initial version |
Your sol is a list, with 1 element:
sage: sol [x == 3]
Then, sol[0]
is a symbolic expression. To get its right hand side, it suffice to use the .rhs()
method:
sage: sol[0] x == 3
sage: sol[0].rhs() 3
![]() | 2 | No.2 Revision |
Your sol is a list, with 1 element:
sage: sol
[x == Then, sol[0]
is a symbolic expression. To get its right hand side, it suffice to use the .rhs()
method:
sage: sol[0]
x == 3
sage: sol[0].rhs()
3
Then, it should be enough to work since the symbolic variable
sage: sol[0].rhs() 3
sage: sol[0].rhs().parent()
Symbolic Ring
That said, it may be a good idea to escape the symbolic ring. If you want to have a genuine integer, you can do:
sage: ZZ(sol[0].rhs())
3
sage: ZZ(sol[0].rhs()).parent()
Integer Ring
If you want an algebraic number:
sage: AA(sol[0].rhs())
3
sage: AA(sol[0].rhs()).parent()
Algebraic Real Field
If you want a floating number:
sage: RR(sol[0].rhs())
3.00000000000000
sage: RR(sol[0].rhs()).parent()
Real Field with 53 bits of precision
![]() | 3 | No.3 Revision |
Your sol sol
is a list, with 1 element:
sage: sol
[x == 3]
Then, sol[0]
is a symbolic expression. To get its right hand side, it suffice to use the .rhs()
method:
sage: sol[0]
x == 3
sage: sol[0].rhs()
3
Then, it should be enough to work since the symbolic variable 3
should be automatically coerced by Sage into a numeric value if needed.needed (and plot should understand symbolic numbers).
sage: sol[0].rhs().parent()
Symbolic Ring
That said, it may be a good idea to escape the symbolic ring. If you want to have a genuine integer, you can do:
sage: ZZ(sol[0].rhs())
3
sage: ZZ(sol[0].rhs()).parent()
Integer Ring
If you want an algebraic number:
sage: AA(sol[0].rhs())
3
sage: AA(sol[0].rhs()).parent()
Algebraic Real Field
If you want a floating number:
sage: RR(sol[0].rhs())
3.00000000000000
sage: RR(sol[0].rhs()).parent()
Real Field with 53 bits of precision