Revision history [back]
 | 1 | initial version |
I don't think there is one but you can define one using a couple of lines of code
def nroot(x,n):
return x**(1/n).n()
nroot(8,3)
| | 1 | initial version |
I don't think there is one but you can define one using a couple of lines of code
def nroot(x,n):
return x**(1/n).n()
nroot(8,3)
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.