Revision history [back]
 | 1 | initial version |  |
How about this:
sage: eq.subs(beta=beta)
x == 1Something strange is that the "dictionary approach" does not work:
sage: eq.subs({beta:beta})
x == beta| | 1 | initial version | |
How about this:
sage: eq.subs(beta=beta)
x == 1Something strange is that the "dictionary approach" does not work:
sage: eq.subs({beta:beta})
x == beta
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.