1 | initial version |
To complete ppurka's answer, here is your code with corrections:
def ListM(p):
UT=[]
for i1 in range(0,p):
for i2 in range(0,p):
for i3 in range(0,p):
for i4 in range(0,p):
UT=UT+[matrix([[i1,i2],[i3,i4]])]
return UT
You may write the next to last line as follows (with the right indentation):
UT.append( matrix([[i1,i2],[i3,i4]]) )
Note that output of ListM(3) looks ugly, but this is a formatting "bug" when you display such a list, output is correct.
Good luck with Sage !
2 | No.2 Revision |
To complete ppurka's answer, here is your code with corrections:
def ListM(p):
UT=[]
for i1 in range(0,p): range(p):
for i2 in range(0,p): range(p):
for i3 in range(0,p):
range(p):
for i4 in range(0,p):
range(p):
UT=UT+[matrix([[i1,i2],[i3,i4]])]
return UT
You may write the next to last line as follows (with the right indentation):
UT.append( matrix([[i1,i2],[i3,i4]]) )
Note that output of ListM(3) looks ugly, but this is a formatting "bug" when you display such a list, output is correct.
Python has very nice syntax for "list comprehensions", you may write:
def rows(p):
return [[x,y] for x in range(p) for y in range(p)]
def ListM(p):
return [matrix([r1,r2]) for r1 in rows(p) for r2 in rows(p)]
Of course in this case using MatrixSpace(GF(3),2,2) is definitely the right solution. Good luck with Sage !
3 | No.3 Revision |
To complete ppurka's answer, here is your code with corrections:
def ListM(p):
UT=[]
for i1 in range(p):
for i2 in range(p):
for i3 in range(p):
for i4 in range(p):
UT=UT+[matrix([[i1,i2],[i3,i4]])]
return UT
Note that output of ListM(3) looks ugly, but this is a formatting "bug" when you display such a list, output is correct.
Python has very nice syntax for "list comprehensions", you may write:
def rows(p):
return [[x,y] for x in range(p) for y in range(p)]
def ListM(p):
return [matrix([r1,r2]) for r1 in rows(p) for r2 in rows(p)]
Of course in this case using MatrixSpace(GF(3),2,2)MatrixSpace(GF(p),2,2) is definitely the right solution.
Good luck with Sage !