| 1 | initial version |
Yeah you are right (2+3I).arg() does not work, but arg(2+3I) works.
But if you want a answer of the form 0.9827 you need arg(2+3*I).n()
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.