Revision history [back]
 | 1 | initial version |
You can try this:
y=function('y',x) var('x,yy,z') f=xy+x^2-y^3x ff=f.diff(x).subs({y.diff(x):z,y:yy}) implicit_plot3d(ff,(x,-3,3),(yy,-3,3),(z,-4,4))
| | 2 | No.2 Revision |
You can try this:
y=function('y',x)
var('x,yy,z')var('x,yy,z')f=xy+x^2-y^3
xxff=f.diff(x).subs({y.diff(x):z,y:yy})ff=f.diff(x).subs({y.diff(x):z,y:yy})
implicit_plot3d(ff,(x,-3,3),(yy,-3,3),(z,-4,4))
| | 3 | No.3 Revision |
You can try this:
y=function('y',x)var('x,yy,z') f=x*y+x^2-y^3*x ff=f.diff(x).subs({y.diff(x):z,y:yy}) implicit_plot3d(ff,(x,-3,3),(yy,-3,3),(z,-4,4))y=function('y',x) var('x,yy,z')
f=xy+x^2-y^3x
ff=f.diff(x).subs({y.diff(x):z,y:yy})
implicit_plot3d(ff,(x,-3,3),(yy,-3,3),(z,-4,4))
| | 4 | No.4 Revision |
You can try this:
y=function('y',x)
var('x,yy,z')
f=x*y+x^2-y^3*x
ff=f.diff(x).subs({y.diff(x):z,y:yy})
implicit_plot3d(ff,(x,-3,3),(yy,-3,3),(z,-4,4))This way you avoid the "solve" issue.
