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I want sage to implicitly differentiate a function for me, say

d/dx f(x)^2 = 2f(x)* f'(x).

I can do this by entering:

var('x')
f=function('f', x)
(f^2).diff(x)

This returns

2 f(x) D[0] (f) (x)

which is correct, but hard for me to read. Can I make sage return:

2 f(x) f'(x)

Thanks.