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[Solved] Difference about divide operator in python2 and sage

asked 2011-12-17 08:00:38 -0500

updated 2011-12-17 08:07:19 -0500

I am writing a package (I want to use "import" to import it into sage).

I found that in the package (say, test.py), if I write

from sage.all import *

def test():
    var('a')
    print -1/2, -a/2, (-1/2)*a

and in sage type

import test; test.test()

I got "-1 -1/2*a -a"

This is different from directly run the above commands from sage.

I know in python 2, -1/2 returns -1. But is there a way to write "minus one half" (-1/2) in a package, say, test.py?

I know I could use load or attach to load a .sage package. However, they don't have namespace and I hope to have namespace as in python.

I could also use 1/2.0, which returns 0.5. But I would want an exact number instead of a float point approximation, for further use.

To summarize, in this case, how to write -1/2 in test.py? Or is there a way to load a sage package with namespace? Thanks!

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answered 2011-12-17 08:07:01 -0500

updated 2011-12-17 08:07:45 -0500

(Let me answer myself instead of deleting the question, for other people to refer to:)

Use

from sage.all import *

def test():
    var('a')
    print -1/Integer(2)

Integer(number) is a sage object, thus don't have the python 2 feature.

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Asked: 2011-12-17 08:00:38 -0500

Seen: 81 times

Last updated: Dec 17 '11