Hello my fellow Sage users. I'm trying to come up ith a formula in sage that relates the number of idempotents in Zn with the number of distinct prime factors that n has. Talking about idempotent rings in my class has gotten a few students confused and this formula will help me better explain the concept. Thank you. Any pointers in the right direction would help greatly.
Here is some code for this:
for n in [2..100]:
print n,': (',len(n.prime_factors()), sum(a.is_idempotent() for a in Zmod(n)),')'
For a fixed n, len(n.prime_factors()) gives the number of prime factors of n and sum(a.is_idempotent() for a in Zmod(n)) gives the number of idempotents.
I guess the number of idempotents should be basically the same as the number of direct summands -- is that right? If so, then maybe you're looking for the direct-sum decomposition of Z/n. Does the fundamental theorem of finitely generated abelian groups give you enough information?
Asked: 2010-12-09 20:56:12 +0200
Seen: 530 times
Last updated: Dec 12 '10
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