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# infinite if inside a loop

Anonymous

I want to define a function that checks if a member of a set is another then print "well".

Let me explain it it the following example:

Assume that Z = Compositions(17, min_part=4).list(), L is some set and f is some function.

How I can write a function such that if f(a), where a is a member of Z, was in L, then that is "well"?

My attempt:

for i in in srange(len(Z)):
for j in srange(i):
if f(Z[i][j]) in L:


I don't know how to finish it because I just know finite if, else, not more.

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## Comments

Can you make your example a little more concrete by providing an actual L and f?

( 2020-12-26 03:01:49 +0200 )edit

## 1 Answer

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Do you want something like this... ?!

def f(a):
return ZZ(a).is_prime()
L = [True]

# we search all partitions of 17 in pieces $\ge 4$, which are each prime
for z in Compositions(17, min_part=4):
f_values = {f(a) for a in z}
if f_values.issubset(L):
print(f"{z} is well")


Results:

[17] is well
[7, 5, 5] is well
[5, 7, 5] is well
[5, 5, 7] is well

more

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Asked: 2020-12-22 22:22:45 +0200

Seen: 76 times

Last updated: Jan 06