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# How to find an example of a 6 by 6 symmetric matrix (which is not identity matrix and does not satisfy $A^2=\text{ Identity matrix}$) which is similar to its inverse?

How to find an example of a 6 by 6 symmetric matrix (which is not identity matrix and does not satisfy $A^2=\text{ Identity matrix}$)which is similar to its inverse? I am trying to find one such example in Sage. Please give some idea to proceed.

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## Comments

The identity matrix.

( 2020-03-24 21:56:06 +0200 )edit

Maybe you can compare the characteristic polynomial of a matrix with the one of its inverse and try to find when the two are equal?

( 2020-03-25 08:17:05 +0200 )edit

ok.can we have at least one such example?

( 2020-03-25 08:47:23 +0200 )edit

On the diagonal put pairs of numbers which are each other's inverse, like 2 and 1/2.

( 2020-03-25 09:13:09 +0200 )edit
3

Does this question have anything to do with SageMath?

( 2020-03-25 13:45:03 +0200 )edit

## 1 Answer

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Let me describe three constructions of matrices which are similar to their inverses over Z. It has little to do with SageMath. That is rather linear algebra.

Construction 1: There are infinitely 2x2 matrices with integral coefficients that are similar over Z to their inverses

sage: A = matrix(2, [1,1,0,1])
sage: B = matrix(2, [1,0,1,1])
sage: P = matrix(2, [-1,0,0,1])
sage: C1 = A
sage: C2 = B
sage: C3 = A * B * A
sage: all(P * C * P**-1 == C**-1 for C in [C1, C2, C3])
True


You can just build your 6x6 matrix M as a block matrix

sage: M = matrix(ZZ, 6)
sage: M[0:2,0:2] = C1
sage: M[2:4,2:4] = C2
sage: M[4:6,4:6] = C3
sage: Q = matrix(ZZ, 6)
sage: Q[0:2,0:2] = Q[2:4,2:4] = Q[4:6,4:6] = P
sage: Q * M * Q**-1 == M**-1
True


Construction 2: The companion matrix of a symmetric polynomial

sage: x = polygen(ZZ, 'x')
sage: a = 13
sage: b = 25
sage: c = 18
sage: M = companion_matrix(X**6 + a*X**5 + b*X**4 + c*X**3 + b*X**2 + a*X + 1)
sage: S = SymmetricGroup(6)
sage: P = S('(1,6)(2,5)(3,4)').matrix()
sage: P * M * P**-1 == M**-1
True


Construction 3: Permutation matrices

sage: S = SymmetricGroup(6)
sage: M = S('(1,2,3,4)(5,6)').matrix()
sage: P = S('(1,4)(2,3)').matrix()
sage: P * M * P**-1 == M**-1
True

more

## Comments

1

And once you found some matrix M satisfying P * M * P**-1 == M**-1 you may create lot more by doing:

sage: Q = random_matrix(ZZ,6,6)
sage: Mnew = Q * M * ~Q
sage: Pnew = Q * P * ~Q
sage: Pnew * Mnew * ~Pnew == ~Mnew
True

( 2020-03-26 08:32:13 +0200 )edit

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Asked: 2020-03-24 21:43:18 +0200

Seen: 162 times

Last updated: Mar 25 '20