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# Pick a point at random on an elliptic curve with specific order

Hi!

I use the function random_point() to pick a point at random on an elliptic curve, but I was wondering if there is a way to pick a point at random that has a specific order (or some useful geometric property that allows me to do that).

So far, brute forcing seems the only way to me (pick a point at random, check its order and iterate until it has the wanted order) but it's obviously very naive!

Thank you for your help!

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## 1 Answer

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Let n be the order of your curve. Let k be desired order of the point. Let P be the random point that you obtained. Compute Q = (n/k)*P With high probability, Q will have order k. Check that. If Q is not of order k, pick a new random point P and repeat the process.

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Given the fact that the distribution of the first random point is uniform (as guaranteed in the doc), how is the distribution of the probability among the points of order k with your method ?

( 2016-12-05 21:52:35 +0200 )edit

It should have the same randomness, but at the level of points of order k. The informal 'proof': if you have a set of random points, which you multiply all by the same scalar (n/k), then you will get a 'compressed with respect to order k', set, which will carry through the randomness to that level.

( 2016-12-06 15:17:39 +0200 )edit
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If you know that the group of order k points on your elliptic curve is cyclic, this approach is fine. However, if it is not, you might miss points:

Suppose E(k)= (Z/2) x (Z/64) , so that the order is n=128 and you want to select a point of order 2 (at random). Then the proposed approach would amount to picking a point P (likely of order 64) and. (n/2)P is guaranteed to be the identity element. Adjusting the approach by computing Q=32P will only give you the non-trivial 2-torsion point that is divisible by 2; never the other.

( 2016-12-09 21:57:07 +0200 )edit

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Asked: 2016-12-05 17:16:21 +0200

Seen: 1,297 times

Last updated: Dec 05 '16