Plotting an element in a polynomial ideal

asked 2015-05-25 03:57:20 +0200

Alasdair
345 ●18 ●31 ●43

I have a polynomial ring in three variables:

P.<x,y,z> = PolynomialRing(QQ)

and I've eliminated the variable t in an ideal generated by several polynomials to obtain an implicit function in just x and y. I'd like to plot this function. But the plot method, applied to an ideal in just two variables, produces the error:

ValueError: Variable 't' not found

So either I need somehow to introduce this variable into the plot, or pull the function out of the polynomial ring so that it can be plotted as a function of real variables with implicit_plot. But I'm not sure how to do either...any advice would be most helpful!

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answered 2015-05-25 08:34:11 +0200

FrédéricC

5125 ●3 ●43 ●111

Something like that

sage: P.<x,y,z> = PolynomialRing(QQ)
sage: I=P.ideal(x*x+y*y-1)
sage: implicit_plot(QQ['x,y'](I.gens()[0]),(x,-2,2),(y,-2,2))

maybe ?

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That works! Many thanks. I don't think I've ever needed the QQ[...] syntax before, even though it's described in the documentation about univariate polynomial rings .

Alasdair ( 2015-05-26 11:00:35 +0200 )edit

That's just a shortcut for PolynomialRing(QQ,['x','y']).

FrédéricC ( 2015-05-26 17:43:21 +0200 )edit

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Asked: 2015-05-25 03:57:20 +0200

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Last updated: May 25 '15

Plotting an element in a polynomial ideal edit