# Dealing with 'NaN' values in lists

 0 Hello! Maybe somebody here has an experience on working with 'NaN' values in Sage. My situation is the following: I need to load some experimentally measured data into a list of float values. But unfortunately, the experimental data set is not "solid" - it has 'NaN' values somewhere inside. What I currently need to perform first of all is to calculate the average value of a list slice. Preferably, simply using 'mean()' if it is possible. So could somebody please give me an advice how to work with such arrays correctly? Thank you. asked Jul 31 '12 v_2e 219 ● 1 ● 10 ● 24

 1 Hello, You should remove the values NaN from your list and then use mean. It is a bit tricky, because of the following behavior sage: float(NaN) == float(NaN) False  The answer may be found here. I reproduce what you want in your case sage: l = [float(NaN), float(0.01), float(19), float(-3), float(NaN)] sage: from math import isnan sage: clean_list = [x for x in l if not isnan(x)] sage: print clean_list [0.01, 19.0, -3.0] sage: mean(clean_list) 5.336666666666667  Vincent posted Jul 31 '12 vdelecroix 866 ● 4 ● 13 ● 27 Hello! Thank you for reply! I tried to use 'is NaN' as you suggested, but the problem is that I need to obtain the data from a text file. But when I use float('NaN'), I get the 'float' type, naturally. Whereas type(NaN) gives me which is different. So I cannot use 'is NaN' construction for the floats obtained by parsing the text file.v_2e (Jul 31 '12)I adapt my answer to your problem...vdelecroix (Jul 31 '12)Thanks! It works! It's a pity I have to check and remove every item in my lists. It may be rather time-consuming with large data sets. Anyway, thank you for the recipe!v_2e (Aug 01 '12)

[hide preview]