Display decimal as a fraction?

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Thank you. But what about numbers such as 4/3, that outputs .3333 to an infinity?

You will get: sage: RR(4/3) 1.33333333333333 sage: QQ(RR(4/3)) 4/3 sage: RR(4/3).exact_rational() 6004799503160661/4503599627370496

So there's no way to convert/simplify, 1.33333333333333, to 4/3 instead of that last humongous number?

Nope. It is related to precision problems. See this for example: sage: 0.1 + 0.1 + 0.1 == 0.3 False

Indeed. 4/3 is not a floating-point number since it can not be written as `p/2^q`. So, when you write sage: a = RR(4/3) You only get an approximation of `4/3`, whose value is sage: a.exact_rational() 6004799503160661/4503599627370496 If you want to recover `4/3` from `a`, you can do sage: a.simplest_rational() 4/3 or, sage: QQ(a) 4/3 But you should understand that two roundings were done during your computation, and that you may have lost something there.