# [Solved] Difference about divide operator in python2 and sage

 0 I am writing a package (I want to use "import" to import it into sage). I found that in the package (say, test.py), if I write from sage.all import * def test(): var('a') print -1/2, -a/2, (-1/2)*a  and in sage type import test; test.test() I got "-1 -1/2*a -a" This is different from directly run the above commands from sage. I know in python 2, -1/2 returns -1. But is there a way to write "minus one half" (-1/2) in a package, say, test.py? I know I could use load or attach to load a .sage package. However, they don't have namespace and I hope to have namespace as in python. I could also use 1/2.0, which returns 0.5. But I would want an exact number instead of a float point approximation, for further use. To summarize, in this case, how to write -1/2 in test.py? Or is there a way to load a sage package with namespace? Thanks! asked Dec 17 '11 tririver 292 ● 2 ● 4 ● 15 http://www.physics.mcgill...

 1 (Let me answer myself instead of deleting the question, for other people to refer to:) Use from sage.all import * def test(): var('a') print -1/Integer(2)  Integer(number) is a sage object, thus don't have the python 2 feature. posted Dec 17 '11 tririver 292 ● 2 ● 4 ● 15 http://www.physics.mcgill...

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