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Since you named one variable n I assume you meant integer. But even this has infinitely many solutions! Sage can give you them for specific n:

sage: [solve(x^n==2*x,x) for n in range(1,5)]
[[x == 0],
 [x == 0, x == 2],
 [x == -sqrt(2), x == sqrt(2), x == 0],
 [x == 1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == -1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == 2^(1/3), x == 0]]

Since you named one variable n I assume you meant integer. But even this has infinitely many solutions! Sage can give you them for specific n:

sage: [solve(x^n==2*x,x) for n in range(1,5)]
[[x == 0],
 [x == 0, x == 2],
 [x == -sqrt(2), x == sqrt(2), x == 0],
 [x == 1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == -1/2*I*sqrt(3)*2^(1/3) - 1/2*2^(1/3), x == 2^(1/3), x == 0]]